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Proof step 1 from proof ocs-del1-if (conclusion)

⊦ #oc(a, x -1l b) = (a ≠ b ∨ ¬ b ∈ x ⊃ #oc(a, x);#oc(a, x) -1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ #oc(a, x -1l b) = (a ≠ b ∨ ¬ b ∈ x ⊃ #oc(a, x);#oc(b, x) - 1)

Rule argument

Additional information

Used simplifier rules: pred-03: ⊦ n -1 = n - 1; from specification nat