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Proof step 4 from proof ocs-del1 (previous step)

∀ a. a ∈ x0 → #oc(a, x0) = 1 ∨ a ∈ x0 -1l a, a = a0 ∨ a ∈ x0 ⊦ a ∈ (a0 ' + x0) -1l a, a ≠ a0 ∧ #oc(a, x0) = 1, ¬ a ∈ x0 ∧ #oc(a, a0 ') = 1

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 5:
∀ a. a ∈ x0 → #oc(a, x0) = 1 ∨ a ∈ x0 -1l a, a = a0 ∨ a ∈ x0 ⊦ a = a0, a ∈ (a0 ' + x0) -1l a, a ≠ a0 ∧ #oc(a, x0) = 1, ¬ a ∈ x0 ∧ #oc(a, a0 ') = 1

Rule argument

fma: a = a0

Additional information

Used simplifier rules: one: ⊦ #oc(a, a ') = 1;%del1-y: ⊦ (a ' + x) -1l a = x; from specification list-del%a: ⊦ (x + y) + z = x + y + z; from specification list Used formulas: a = a0