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Proof step 1 from proof ocs-same-length-all (conclusion)

⊦ #oc(a, x) = # x ↔ (∀ b. b ∈ x → b = a)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ #oc(a, x) = # x ↔ x = mklist(a, # x)
Proof step 3:
⊦ x = mklist(a, # x) ↔ (∀ b. b ∈ x → b = a)

Rule argument

spec: inst: name: ocs-same-length-mklist seq: ⊦ #oc(a, x) = # x ↔ x = mklist(a, # x) subst: [x, a] → [x, a] flags: rewrite, current

Additional information

Used terms: x, a