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Proof step 10 from proof ocs-same-length-all (previous step)

∀ a. x0 = mklist(a, # x0) ↔ (∀ b. b ∈ x0 → b = a) ⊦ a0 = a ∧ x0 = mklist(a, # x0) ↔ (∀ b. b = a0 ∨ b ∈ x0 → b = a)

User applied rule all left

And obtained the following new goals

Proof step 11:
x0 = mklist(a, # x0) ↔ (∀ b. b ∈ x0 → b = a), ∀ a. x0 = mklist(a, # x0) ↔ (∀ b. b ∈ x0 → b = a) ⊦ a0 = a ∧ x0 = mklist(a, # x0) ↔ (∀ b. b = a0 ∨ b ∈ x0 → b = a)

Rule argument

pos: left 1 terms: a abort: F discard: F computed: T

Additional information

Used terms: a