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Proof step 10 from proof ocs-same-length-mklist (previous step)

∀ a. #oc(a, x0) = # x0 ↔ x0 = mklist(a, # x0) ⊦ #oc(a0, x0) = # x0 ↔ x0 = mklist(a0, # x0)

User applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: a0 abort: F discard: T computed: T

Additional information

Used terms: a0