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Proof step 14 from proof ocs-same-length-mklist (previous step)

¬ # x0 < #oc(a, x0), #oc(a, x0) = # x0 + 1, ∀ a. #oc(a, x0) = # x0 ↔ x0 = mklist(a, # x0) ⊦ a = a0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 2 flags: discard

Additional information

Used simplifier rules: s: ⊦ m < n + 1 ↔ ¬ n < m; from specification nat-basic2%ref-1: ⊦ ¬ n < n; from specification nat-basic1%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2