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Proof step 13 from proof ocs-sw (previous step)

¬(x[m, x[n]][n] ≠ x[m] ∧ n < # x[m, x[n]]), n < # x, m < # x ⊦ x[n] = x[m], #oc(x[m], x[m, x[n]][n, x[m]]) = #oc(x[m], x), x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
x[m, x[n]][n] = x[m], n < # x, m < # x ⊦ x[n] = x[m], #oc(x[m], x[m, x[n]][n, x[m]]) = #oc(x[m], x), x = []

Rule argument

Additional information

Used simplifier rules: put-length: ⊦ n < # x → # x[n, a] = # x; from specification list-del