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Proof step 1 from proof perm-all (conclusion)

⊦ perm(x, y) ↔ (∀ a. a ∈ x ∨ a ∈ y → #oc(a, x) = #oc(a, y))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ perm(x, y) ↔ x ⊆m y ∧ y ⊆m x
Proof step 3:
⊦ x ⊆m y ∧ y ⊆m x ↔ (∀ a. a ∈ x ∨ a ∈ y → #oc(a, x) = #oc(a, y))

Rule argument

spec: list-perm inst: name: perm seq: ⊦ perm(x, y) ↔ x ⊆m y ∧ y ⊆m x subst: [y, x] → [y, x] flags: rewrite, current

Additional information

Used terms: y, x