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Proof step 5 from proof perm-all (
previous step
)
(∀ a. #oc(a, x) ≤ #oc(a, y)) ∧ (∀ a. #oc(a, y) ≤ #oc(a, x)) ⊦ ∀ a. a ∈ x ∨ a ∈ y → #oc(a, x) = #oc(a, y)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
a ∈ x ∨ a ∈ y, ∀ a. #oc(a, x) ≤ #oc(a, y), ∀ a. #oc(a, y) ≤ #oc(a, x) ⊦ #oc(a, x) = #oc(a, y)
Rule argument
Additional information