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Proof step 18 from proof perm-del-01 (previous step)

perm(x -l a, z), perm(x, y), a0 ∈ y ∨ a0 ∈ x → #oc(a0, y) = #oc(a0, x), a0 ∈ y ∨ a0 ∈ z, a0 ∈ z ∨ a0 ∈ x → #oc(a0, z) = #oc(a0, x) ⊦ #oc(a0, y) = #oc(a0, z), a0 = a

User applied rule case distinction

And closed the goal!

Rule argument

pos: left 4

Additional information

Used simplifier rules: notin: ⊦ ¬ a ∈ x → #oc(a, x) = 0;%in-05: ⊦ a ∈ x → #oc(a, x) ≠ 0;%notin: ⊦ ¬ a ∈ x → #oc(a, x) = 0;%in-05: ⊦ a ∈ x → #oc(a, x) ≠ 0;