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Proof step 2 from proof perm-del (previous step)

perm(x, y), perm(y, x) ⊦ perm(x -1l a, z) ↔ perm(y -1l a, z)

Heuristic pl case distinction applied rule case distinction

And obtained the following new goals

Proof step 3:
perm(x -1l a, z), perm(x, y), perm(y, x) ⊦ perm(y -1l a, z)
Proof step 6:
perm(y -1l a, z), perm(x, y), perm(y, x) ⊦ perm(x -1l a, z)

Rule argument

pos: right 1

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