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Proof step 11 from proof perm-put-del1 (previous step)

y[n] ∈ y, n < # y, y[n] ∈ y[n, a] -1l a ∨ y[n] ∈ y -1l y[n] ⊦ y = [], #oc(y[n], y[n, a] -1l a) = #oc(y[n], y) - 1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 12:
#oc(y[n], y) = m + 1 ∧ #oc(y[n], y) ≠ 0, y[n] ∈ y, n < # y, y[n] ∈ y[n, a] -1l a ∨ y[n] ∈ y -1l y[n] ⊦ y = [], #oc(y[n], y[n, a] -1l a) = m

Rule argument

spec: nat inst: name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [#oc(y[n], y), m] flags:

Additional information

Used simplifier rules: in-05: ⊦ a ∈ x → #oc(a, x) ≠ 0;%n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: #oc(y[n], y), m