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Proof step 21 from proof perm-put-del1 (previous step)

¬ a0 ≠ a, n < # y, a0 ∈ y[n, a] -1l a ∨ a0 ∈ y ⊦ y = [], #oc(a0, y[n, a] -1l a) = #oc(a0, y), a0 = y[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
n < # y, a ∈ y ⊦ y = [], #oc(a, y[n, a] -1l a) = #oc(a, y), a = y[n]

Rule argument

Additional information

Used simplifier rules: put-del1-in: ⊦ x[m] ≠ a ∧ m < # x → (a ∈ x[m, a] -1l a ↔ a ∈ x); from specification list-del