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Proof step 1 from proof perm-rec (conclusion)

⊦ perm(y, z + a ' + x) ↔ a ∈ y ∧ perm(y -1l a, z + x)

User applied rule case distinction

And obtained the following new goals

Proof step 2:
perm(y, z + a ' + x) ⊦ a ∈ y ∧ perm(y -1l a, z + x)
Proof step 5:
a ∈ y ∧ perm(y -1l a, z + x) ⊦ perm(y, z + a ' + x)

Rule argument

pos: right 1

Additional information