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Proof step 11 from proof shift-03 (previous step)

perm(x1 + a ' + x0, y -1l a0), perm(x1 + x0, (y -1l a0) -1l a), a ∈ y, a ∈ y -1l a0, perm(y -1l a0, x1 + a ' + x0), perm((y -1l a0) -1l a, x1 + x0) ⊦ a0 ∈ y ↔ a0 ∈ y -1l a

User applied rule cut formula

And closed the goal!

Rule argument

fma: a = a0

Additional information

Used simplifier rules: in-04: ⊦ a ∈ x ∧ a ≠ b → a ∈ x -1l b; from specification list-del%del1-in: ⊦ a ≠ b → (a ∈ x -1l b ↔ a ∈ x); from specification list-del%in-02-01: ⊦ ¬ a ∈ x → x -1l a = x; from specification list-del Used formulas: a = a0