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Proof step 5 from proof size-perm (previous step)

# x = # y, ∀ a. a ∈ y → a ∈ x, ∀ a. a ∈ x → a ∈ y ⊦ dups(x), dups(y), #oc(a, x) ≤ #oc(a, y) ∧ #oc(a0, y) ≤ #oc(a0, x)

User applied rule case distinction

And obtained the following new goals

Proof step 6:
# x = # y, ∀ a. a ∈ y → a ∈ x, ∀ a. a ∈ x → a ∈ y ⊦ #oc(a, x) ≤ #oc(a, y), dups(x), dups(y)
Proof step 8:
# x = # y, ∀ a. a ∈ y → a ∈ x, ∀ a. a ∈ x → a ∈ y ⊦ #oc(a0, y) ≤ #oc(a0, x), dups(x), dups(y)

Rule argument

pos: right 3

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