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Proof step 9 from proof size-perm (previous step)

# x = # y, ∀ a. a ∈ y → a ∈ x, ∀ a. a ∈ x → a ∈ y ⊦ #oc(a0, y) ≤ #oc(a0, x), dups(x), dups(y)

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 10:
# x = # y, ∀ a. a ∈ y → a ∈ x, a0 ∈ x → a0 ∈ y, ∀ a. a ∈ x → a ∈ y ⊦ #oc(a0, y) ≤ #oc(a0, x), dups(x), dups(y)

Rule argument

pos: left 3 terms: a0

Additional information

Used terms: a0