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Proof step 12 from proof sub-del-any (previous step)

∀ a. #oc(a, x) ≤ #oc(a, y) ⊦ a0 = a, #oc(a0, x) ≤ #oc(a0, y) ∧ #oc(a, x) ≤ #oc(a, y)

User applied rule all left

And obtained the following new goals

Proof step 13:
#oc(a, x) ≤ #oc(a, y), ∀ a. #oc(a, x) ≤ #oc(a, y) ⊦ a0 = a, #oc(a0, x) ≤ #oc(a0, y) ∧ #oc(a, x) ≤ #oc(a, y)

Rule argument

pos: left 1 terms: a abort: F discard: F computed: T

Additional information

Used terms: a