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Proof step 16 from proof sub-del-any (previous step)

#oc(a0, y) < #oc(a0, x), #oc(a, x) ≤ #oc(a, y), a0 ∈ x, ∀ a0. #oc(a0, x -l a) ≤ #oc(a0, y -l a) ⊦

User applied rule all left

And obtained the following new goals

Proof step 17:
#oc(a0, y) < #oc(a0, x), #oc(a, x) ≤ #oc(a, y), a0 ∈ x, #oc(a0, x -l a) ≤ #oc(a0, y -l a), ∀ a0. #oc(a0, x -l a) ≤ #oc(a0, y -l a) ⊦

Rule argument

pos: left 4 terms: a0 abort: F discard: F computed: F

Additional information

Used terms: a0