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Proof step 6 from proof sub-del-any (previous step)

∀ a. #oc(a, x) ≤ #oc(a, y) ⊦ (∀ a0. #oc(a0, x -l a) ≤ #oc(a0, y -l a)) ∧ #oc(a, x) ≤ #oc(a, y)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information