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Proof step 2 from proof subapp-02 (previous step)

x ⊆m x0 ⊦ x ⊆m x0 + y

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ x ⊆m y ↔ (∀ a. #oc(a, x) ≤ #oc(a, y))
Proof step 4:
x ⊆m x0 ⊦ ∀ a. #oc(a, x) ≤ #oc(a, x0 + y)

Rule argument

spec: list-perm inst: name: msubset seq: ⊦ x ⊆m y ↔ (∀ a. #oc(a, x) ≤ #oc(a, y)) subst: [y, x] → [x0 + y, x] flags: rewrite, current

Additional information

Used terms: x0 + y, x