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Proof step 5 from proof subdel-01 (previous step)

#oc(a0, (y + y0) -1l a) < #oc(a0, x), a ∈ y0, x ⊆m y + (y0 -1l a), a0 ∈ x ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ x ⊆m y ↔ (∀ a. #oc(a, x) ≤ #oc(a, y))
Proof step 7:
#oc(a0, (y + y0) -1l a) < #oc(a0, x), a ∈ y0, ∀ a0. #oc(a0, x) ≤ #oc(a0, y + (y0 -1l a)), a0 ∈ x ⊦

Rule argument

spec: list-perm inst: name: msubset seq: ⊦ x ⊆m y ↔ (∀ a. #oc(a, x) ≤ #oc(a, y)) subst: [y, x] → [y + (y0 -1l a), x] flags: rewrite, current

Additional information

Used terms: y + (y0 -1l a), x