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Proof step 1 from proof subdel-02 (conclusion)

⊦ x -1l a ⊆m y ↔ x -l a ⊆m y -l a ∧ #oc(a, x) ≤ #oc(a, y) + 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ x ⊆m y ↔ x -l a ⊆m y -l a ∧ #oc(a, x) ≤ #oc(a, y)
Proof step 3:
⊦ (x -1l a) -l a ⊆m y -l a ∧ #oc(a, x -1l a) ≤ #oc(a, y) ↔ x -l a ⊆m y -l a ∧ #oc(a, x) ≤ #oc(a, y) + 1

Rule argument

spec: inst: name: sub-del-any seq: ⊦ x ⊆m y ↔ x -l a ⊆m y -l a ∧ #oc(a, x) ≤ #oc(a, y) subst: [a, y, x] → [a, y, x -1l a] flags: rewrite, current

Additional information

Used terms: a, y, x -1l a