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Proof step 16 from proof subsize (previous step)

#oc(a0, y0) + #oc(a0, z) < #oc(a0, x0), # y0 + # z < # x0, #oc(a, x0) ≤ #oc(a, y0) + #oc(a, z), ∀ a0. #oc(a0, x0) ≤ #oc(a0, y0) + #oc(a0, z) ⊦ x0 = [], ∃ y. # y < # x0 ∧ (∀ a. #oc(a, x0) ≤ #oc(a, y))

User applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: a0 abort: F discard: F computed: F

Additional information

Used simplifier rules: fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%ref-1: ⊦ ¬ n < n; from specification nat-basic1 Used terms: a0