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Proof step 4 from proof subsize (previous step)

# y ≤ # x0, (∃ y. # y < # x0 ∧ (∀ a. #oc(a, x0) ≤ #oc(a, y))) → x0 = [], ∀ a0. #oc(a0, a ') + #oc(a0, x0) ≤ #oc(a0, y) ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 5:
x0 = [], # y ≤ # x0, (∃ y. # y < # x0 ∧ (∀ a. #oc(a, x0) ≤ #oc(a, y))) → x0 = [], ∀ a0. #oc(a0, a ') + #oc(a0, x0) ≤ #oc(a0, y) ⊦
Proof step 7:
# y ≤ # x0, (∃ y. # y < # x0 ∧ (∀ a. #oc(a, x0) ≤ #oc(a, y))) → x0 = [], ∀ a0. #oc(a0, a ') + #oc(a0, x0) ≤ #oc(a0, y) ⊦ x0 = []

Rule argument

fma: x0 = []

Additional information

Used formulas: x0 = []