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Proof step 8 from proof subsize (previous step)

# y ≤ # x0, ∀ a0. #oc(a0, a ') + #oc(a0, x0) ≤ #oc(a0, y) ⊦ x0 = [], ∃ y. # y < # x0 ∧ (∀ a. #oc(a, x0) ≤ #oc(a, y))

User applied rule all left

And obtained the following new goals

Proof step 9:
# y ≤ # x0, #oc(a, a ') + #oc(a, x0) ≤ #oc(a, y), ∀ a0. #oc(a0, a ') + #oc(a0, x0) ≤ #oc(a0, y) ⊦ x0 = [], ∃ y. # y < # x0 ∧ (∀ a. #oc(a, x0) ≤ #oc(a, y))

Rule argument

pos: left 2 terms: a abort: F discard: F computed: T

Additional information

Used terms: a