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Proof step 14 from proof del1-01 (previous step)

∀ y, a. filter(rmdup(x0), y -1l a) = filter(rmdup(x0), y) ∨ a ∈ x0 ⊦ a = a0, filter(rmdup(x0), y -1l a) = filter(rmdup(x0), y), a0 ∈ x0, a ∈ x0, a0 ∈ y

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: y, a

Additional information

Used terms: y, a