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Proof step 1 from proof del1 (conclusion)
⊦ ¬ a ∈ x → filter(x, y -1l a) = filter(x, y)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
⊦ filter(x, y -1l a) = filter(x, y), a ∈ x
Rule argument
Additional information