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Proof step 8 from proof diff-dups (previous step)

dups(x0 \ y), ∀ y0. ¬ dups(x0 \ y0) ⊦ dups(x0), a ∈ y, a ∈ x0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: y

Additional information

Used terms: y