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Proof step 7 from proof diff-empty-all (previous step)

∀ y. x0 \ y = [] ↔ (∀ a. a ∈ x0 → a ∈ y), ∀ a0. a0 = a ∨ a0 ∈ x0 → a0 ∈ y ⊦ a ∈ y

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: a

Additional information

Used terms: a