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Proof step 3 from proof diff-empty-sub (previous step)

⊦ (∀ a. a ∈ x → a ∈ y) ↔ x ⊆ y

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: list-set inst: name: subset seq: ⊦ x ⊆ y ↔ (∀ a. a ∈ x → a ∈ y) subst: [y, x] → [y, x] flags: rewrite, current

Additional information

Used terms: y, x