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Proof step 14 from proof diff-twice-union (
previous step
)
a ∈ z, ∀ y, z. (x0 \ y) \ z = x0 \ rmdup(y + z) ⊦ (x0 \ y) \ z = x0 \ rmdup(y + z), a ∈ y
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 2 terms: y, z
Additional information
Used terms: y, z