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Proof step 12 from proof diff-unchanged (previous step)

x0 \ y = x0, a0 ∈ x0, a0 ∈ y, ∀ a. ¬ a ∈ x0 ∨ ¬ a ∈ y ⊦ a ∈ y

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: a0

Additional information

Used terms: a0