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Proof step 23 from proof diff-union (
previous step
)
∀ z. rmdup(y0) \ z = rmdup(y0 \ z) ⊦ rmdup(y0) \ z = rmdup(y0 \ z), a ∈ z, a ∈ y0
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 1 terms: z
Additional information
Used terms: z