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Proof step 32 from proof diff-union (previous step)

a ∈ x0 ∨ a ∈ y, a ∈ z, ∀ y0, z0. rmdup(x0 + y0) \ z0 = rmdup((x0 \ z0) + (y0 \ z0)) ⊦ rmdup(x0 + y) \ z = rmdup((x0 \ z) + (y \ z))

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: y, z

Additional information

Used terms: y, z