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Proof step 8 from proof diff-union (previous step)

a ∈ y0, ∀ z. rmdup(y0) \ z = rmdup(y0 \ z) ⊦ rmdup(y0) \ z = rmdup((a ' + y0) \ z)

User applied rule all left

And obtained the following new goals

Proof step 9:
a ∈ y0, rmdup(y0) \ z = rmdup(y0 \ z) ⊦ rmdup(y0) \ z = rmdup((a ' + y0) \ z)

Rule argument

pos: left 2 terms: z abort: F discard: T computed: T

Additional information

Used terms: z