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Proof step 13 from proof rmdup (previous step)

∀ a0. a0 ∈ x → a0 = a ∨ a0 ∈ y0, ∀ x. (∀ a. a ∈ rmdup(x) → a ∈ y0) ↔ (∀ a. a ∈ x → a ∈ y0) ⊦ ∀ a0. a0 ∈ rmdup(x) → a0 = a ∨ a0 ∈ y0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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