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Proof step 4 from proof rmdup (previous step)

⊦ (∀ a. ¬ a ∈ rmdup(x)) ↔ (∀ a. ¬ a ∈ x)

Heuristic pl case distinction applied rule case distinction

And obtained the following new goals

Proof step 5:
∀ a. ¬ a ∈ rmdup(x) ⊦ ∀ a. ¬ a ∈ x
Proof step 7:
∀ a. ¬ a ∈ x ⊦ ∀ a. ¬ a ∈ rmdup(x)

Rule argument

pos: right 1

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