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Proof step 1 from proof sub-size-01 (conclusion)

⊦ x ⊆ y ∧ ¬ dups(x) → (# y < # x ↔ false)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# y < # x, x ⊆ y ⊦ x = [], dups(x)

Rule argument

Additional information

Used simplifier rules: l: ⊦ # x = 0 ↔ x = []; from specification list-data%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1