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Proof step 1 from proof sub-size (conclusion)

⊦ x ⊆ y ∧ ¬ dups(x) → # x ≤ # y

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: sub-size-01: ⊦ x ⊆ y ∧ ¬ dups(x) → (# y < # x ↔ false);%lels-01: ⊦ ¬ m ≤ n ↔ n < m; from specification nat