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Proof step 1 from proof app-02-ant (conclusion)

⊦ ¬ x + y ≠ [] ↔ x = [] ∧ y = []

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Nil: ⊦ [] + x = x;%a: ⊦ (x + y) + z = x + y + z;%app-02: ⊦ x + y = [] ↔ x = [] ∧ y = [];