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Proof step 4 from proof app-03 (previous step)

x + a ' + y0 = z + a ' + y0, ∀ x, z. x + y0 = z + y0 → x = z ⊦ x = z

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: x + a ', z + a '

Additional information

Used simplifier rules: a: ⊦ (x + y) + z = x + y + z;%app-06: ⊦ x + a ' = y + b ' ↔ x = y ∧ a = b; Used terms: x + a ', z + a '