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Proof step 1 from proof app-07 (conclusion)

⊦ a ' + x = b ' + x ↔ a = b

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: app-03: ⊦ x + y = z + y ↔ x = z;%c-04: ⊦ a ' = b ' ↔ a = b;%a: ⊦ (x + y) + z = x + y + z;