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Proof step 6 from proof append-size-less (previous step)

x3 + x0 = x + x2, # x3 < # x, ∀ x0, x1, x2. x3 + x0 = x1 + x2 ∧ # x3 < # x1 → x1 = [] ∨ (∃ y. x1 = x3 + y ∧ x0 = y + x2) ⊦ x = [], ∃ y. x = x3 + y ∧ x0 = y + x2

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: x0, x, x2

Additional information

Used terms: x0, x, x2