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Proof step 1 from proof c-09 (conclusion)

⊦ x = [] ∨ x = x.first ' + x.rest

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: fr: ⊦ x ≠ [] → x.first ' + x.rest = x;%a: ⊦ (x + y) + z = x + y + z;