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Proof step 1 from proof eq-02 (conclusion)

⊦ c ' + z = x0 + a ' ∧ x + b0 ' + c ' + z = b ' + y0 + a0 ' → a = a0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: in-15: ⊦ x + a ' = y → a ∈ y;%a: ⊦ (x + y) + z = x + y + z;%in-14: ⊦ a ' + x = y → a ∈ y;%app-06: ⊦ x + a ' = y + b ' ↔ x = y ∧ a = b;