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Proof step 1 from proof in-17 (conclusion)

⊦ a ∈ b ' ↔ a = b

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ a ∈ x ↔ (∃ y, z. x = y + (a + z))
Proof step 3:
⊦ (∃ y, z. b ' = y + (a + z)) ↔ a = b

Rule argument

spec: list inst: name: In seq: ⊦ a ∈ x ↔ (∃ y, z. x = y + (a + z)) subst: [x, a] → [b ', a] flags: rewrite, current

Additional information

Used terms: b ', a