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Proof step 10 from proof in-rec (previous step)

b ' + x = y + a ' + z ⊦ y = [], a = b, ∃ y, z. x = y + a ' + z

User applied rule exists right

And obtained the following new goals

Proof step 11:
b ' + x = y + a ' + z ⊦ y = [], a = b, x = y.rest + a ' + z, ∃ y, z. x = y + a ' + z

Rule argument

pos: right 3 terms: y.rest, z abort: F discard: F computed: F

Additional information

Used terms: y.rest, z