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Proof step 13 from proof in-rec (previous step)

a = b ∨ x = y + a ' + z ⊦ ∃ y, z. b ' + x = y + a ' + z

User applied rule exists right

And obtained the following new goals

Proof step 14:
a = b ∨ x = y + a ' + z ⊦ b ' + x = (b ' + y) + a ' + z, ∃ y, z. b ' + x = y + a ' + z

Rule argument

pos: right 1 terms: b ' + y, z abort: F discard: F computed: F

Additional information

Used terms: b ' + y, z