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Proof step 1 from proof lastdiv-rew (conclusion)

⊦ x ≠ [] ↔ (∃ y, a. x = y + a ')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ x = [], ∃ y, a. x = y + a '

Rule argument

Additional information

Used simplifier rules: e-02: ⊦ x + a ' ≠ [];%a: ⊦ (x + y) + z = x + y + z;